Posted July 29, 20168 yr ;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;; ;;;another little markov-game => markov with "global-tendency" ;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;; ;;;a "neutral table with 4 values" (setq transitions '((1 (1 1) (2 1) (3 1) (4 1)) (2 (1 1) (2 1) (3 1) (4 1)) (3 (1 1) (2 1) (3 1) (4 1)) (3 (1 1) (2 1) (3 1) (4 1)) (4 (1 1) (2 1) (3 1) (4 1)))) ;;;subfunctions (defun filter-first-last (n sequence) (car (filter-last n sequence))) (defun substitute-transition-weight (transition-list value new-weight) (loop for j in transition-list collect (append (list (first j)) (loop repeat (1- (length j)) for cnt = 1 then (incf cnt) when (equal (first (nth cnt j)) value) collect (list (first (nth cnt j)) new-weight) else collect (nth cnt j))))) ;;;mainfuction (defun markov-with-tendency (transitions size generations value) (loop repeat generations with list = (gen-markov-from-transitions transitions :size size :start 1) with weight = 1 with weight-add = 0 do (setq transitions (substitute-transition-weight transitions value weight)) append (setq list (gen-markov-from-transitions transitions :size size :start (filter-first-last 1 list))) do (incf weight (incf weight-add)))) ;;;some simulations => evaluate!!! (list-plot (markov-with-tendency transitions 10 20 1) :point-radius 0 :style :fill) (list-plot (list (markov-with-tendency transitions 10 20 1) (markov-with-tendency transitions 10 20 2) (markov-with-tendency transitions 10 20 4)) :point-radius 0 :style :fill) (list-plot ;;non-neutral-table (markov-with-tendency '((1 (1 1) (2 4)) (2 (1 1) (4 1)) (3 (1 4) (3 5) (4 3)) (3 (1 1) (2 4) (3 2)) (4 (1 1) (3 2) (4 3))) 10 20 1) :point-radius 0 :style :fill)
August 5, 20168 yr Author you are right, sorry. no computer with me... think you could replace filter-first-last by: (car (last list))
Create an account or sign in to comment