I do not understand the outcome, if I use augmentation inside the counterpoint function. See example, in my understanding: bar 3 should be empty and the clarinet should start again in bar 4!? Is it only possible to use augmentation in all voices at the same time, why does the time signature is different from span in bar 2? 

Did I get something wrong?

 

Best wishes 

 

(setf seq1 '(s c4 mf e. cs4 e e4 q. fs4 tie q fs4)) 
(setf seq2 '(e f4 e. g4 s bb4 e b4))
(setf seq3 '( s d4 qs eb4 s gs4 e. a4))

(counterpoint
 (list seq1 seq2 seq3)
 '(
   #|1|# ((1 - 1) :span nil :methods (- - (i t5)))
   #|2|# ((1 2 1) :span 4/8 :methods ((la2 t10 i) - la2))
   #|3|# ((- - -) :span 3/8 :methods (- - -))
   #|4|# ((- 1 -) :span nil :methods (- - -))
   )
 :global-methods '(- - -)
 :global-polyphony nil
 :index 'vox
 )
 
(ps 'gm
    :fl (list vox1)
    :cl (list vox2)
    :hn (list vox3))

 

The given span is the master, therefore this is a bug - well spotted. This only happens with length augmentation. This is fix in 3.0.29233. 
 

thank you very much, excellent support!!!